Answer
$\color{blue}{\bf{ 68 }}$
Work Step by Step
We are given the two functions $\bf{f}$ and $\bf{g}$
$\bf{f(x) = 3x^2 - 4 }$ and $\bf{g(x) = x^2 - 3x - 4 }$
We are asked to find $\bf{ ( f+g )(-4) }$
$( f+g )(-4) = 3(-4)^2 - 4+ (-4)^2 - 3(-4) - 4 $
$3(16) - 4+ 16 +12 - 4 $
$48 - 4+ 28 - 4 $
$44+24$
$\color{blue}{\bf{ 68 }}$
