Answer
$\color{blue}{\bf{ -\dfrac{23 }{4} }}$
Work Step by Step
We are given the two functions $\bf{f}$ and $\bf{g}$
$\bf{f(x) = 3x^2 - 4 }$ and $\bf{g(x) = x^2 - 3x - 4 }$
We are asked to find $\bf{ ( \dfrac{f}{g} )(3) }$
$( \dfrac{f}{g} )(3) = \dfrac{3(3)^2 - 4 }{(3)^2 - 3(3) - 4} $
$ \dfrac{3(9) - 4 }{9 - 9 - 4} $
$ \dfrac{27 - 4 }{ - 4} $
$\color{blue}{\bf{ -\dfrac{23 }{4} }}$
