Answer
undefined.
Work Step by Step
Step 1. Given $f(x)=3x^2-4$ and $g(x)=x^2-3x-4$, we have $f(-1)=3(-1)^2-4=-1$ and $g(-1)=(-1)^2-3(-1)-4=0$
Step 2. Thus $(\frac{f}{g})(-1)=\frac{f(-1)}{g(-1)}$. As $g(-1)=0$, the ratio is undefined.
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