Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.8 Function Operations and Composition - 2.8 Exercises - Page 290: 94

Answer

$\color{blue}{\bf{ ( f \text{ }\omicron\text{ g} )(x) = ( g \text{ }\omicron\text{ f} )(x) =x }}$

Work Step by Step

We are given the two functions $\bf{f}$ and $\bf{g}$ $\bf{f(x) = -3x }$ and $\bf{g(x) = -\dfrac{1}{3} x }$ we are asked to show that $\bf{ ( f \text{ }\omicron\text{ g} )(x) = ( g \text{ }\omicron\text{ f} )(x) =x }$ $ ( f \text{ }\omicron\text{ g} )(x)=( g \text{ }\omicron\text{ f} )(x) $ $ -3( - \dfrac{1}{3} x ) = -\dfrac{1}{3} (-3x) $ $ \dfrac{-3}{-3} x = \dfrac{-3}{-3}x $ $ 1 x = 1 x $ $ x = x $ Thus we see that, $\color{blue}{\bf{ ( f \text{ }\omicron\text{ g} )(x) = ( g \text{ }\omicron\text{ f} )(x) =x }}$
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