Answer
See explanations.
Work Step by Step
Step 1. Given $f(x)=3x-2, g(x)=2x-3$, we have $(f\circ g)(x)=f(g(x))=3(2x-3)-2=6x-11$
Step 2. $(g\circ f)(x)=g(f(x))=2(3x-2)-3=6x-7$
Step 3. We conclude that $(f\circ g)(x)\ne (g\circ f)(x)$ for this case.
