Answer
$\color{blue}{\bf{ f(x)= \sqrt{x}+12 \text{ ; } g(x)= 6x }}$
$\color{blue}{\bf{\text{or other equivalent functions}}}$
Work Step by Step
We are given the function $\bf{h(x)= \sqrt{6x}+12 }$ and are asked to find two functions ${f(x)}$ and ${g(x)}$ such that $( f \text{ }\omicron\text{ g} )(x) =h(x)$
There are many ways to do this, for example:
$\color{magenta}{f(x)= \sqrt{x}+12 }$ and $\color{lime}{g(x)= 6x }$
$\color{magenta}{ \sqrt{\color{lime}{ 6x }}+12 }$
$\color{blue}{\bf{ f(x)= \sqrt{x}+12 \text{ ; } g(x)= 6x }}$
$\color{blue}{\bf{\text{or other equivalent functions}}}$