Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.3 Functions - 2.3 Exercises: 33

Answer

The given relation defines $y$ as a function of $x$. domain: $(-\infty, +\infty)$ range: $[0, +\infty)$

Work Step by Step

Note that for every value of $x$, the equation $y=x^2$ gives only one value of $y$. This means that every $x$ is paired with only one value of $y$. Thus, the given relation defines $y$ as a function of $x$. The value of $x$ can be any real number so the domain is $(-\infty, +\infty)$. The value of $x^2$ is zero or higher. Thus, the range is $[0, +\infty)$ .
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