Answer
$f(3t-2)=-9t+10$
Work Step by Step
To find the value of $f(3t-2)$, substitute $3t-2$ to $x$ in $f(x)$ to obtain:
$f(x)=-3x+4
\\f(3t-2)=-3(3t-2)+4
\\f(3t-2) = -3(3t) +(-3)(-2)+4
\\f(3t-2)=-9t+6+4
\\f(3t-2)=-9t+10$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 2 - Graphs and Functions - 2.3 Functions - 2.3 Exercises - Page 216: 66
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