Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.3 Functions - 2.3 Exercises: 48

Answer

The given relation defines $y$ as a function of $x$. domain: $(-\infty, 5) \cup (5, +\infty)$ range: $(-\infty, 0) \cup (0, +\infty)$

Work Step by Step

The given equation will give only one value of $y$ for every value of $x$ within its domain. This means that each $x$ is paired with only one value of $y$. Thus, the given relation defines $y$ as a function of $x$. The denominator is not allowed to be zero. Since $5$ will make the given expression's denominator equal to zero, then $x$ cannot be $5$. Thus, the domain is $(-\infty, 5) \cup (5, +\infty)$. Note that when $-7$ is divided by any non-zero number, the quotient will never be equal to zero. Thus, the value of $y$ can be any real number except zero. In interval notation, the range is $(-\infty, 0) \cup (0, +\infty)$.
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