Answer
$(x+4)^2+(y-3)^2=106$
Work Step by Step
Step 1. Assume the radius is $r$, the equation should be: $(x+4)^2+(y-3)^2=r^2$
Step 2. Use the condition that point $(5,8)$ is on the circle, we have $(5+4)^2+(8-3)^2=r^2$ which gives $r^2=106$, thus the equation is: $(x+4)^2+(y-3)^2=106$
