Answer
$(x-3)^2+(y-2)^2=4$
Work Step by Step
Step 1. Since the circle touches the x-axis at exactly one point, its radius should be the absolute value of the center y-coordinate, that is $r=2$
Step 2. With the center at $(3,2)$, the equation is: $(x-3)^2+(y-2)^2=4$
