Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.1 Rectangular Coordinates and Graphs - 2.1 Exercises: 8

Answer

True.

Work Step by Step

If there exists an x-intercept, the y-coordinate of that point must be zero. If $y=0,$ $x^{2}-2=0\qquad/$+$2$ $x^{2}=+2$ $x=+\sqrt{2}$ or $x=-\sqrt{2}.$ So, there are two x-intercepts, $(-\sqrt{2},0)$ and $(\sqrt{2},0)$ (and no other)
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