Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.1 Rectangular Coordinates and Graphs - 2.1 Exercises: 6

Answer

5

Work Step by Step

$d(P, R)=\sqrt{(x_{2}-x_{\mathrm{I}})^{2}+(y_{2}-y_{1})^{2}}$ ----------- $P(0,0), R(-3,4),$ $d(P, R)=\sqrt{(-3-0)^{2}+(4-0)^{2}}$ $=\sqrt{9+16}=\sqrt{25}=5$
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