Chapter 2 - Graphs and Functions - 2.1 Rectangular Coordinates and Graphs - 2.1 Exercises - Page 192: 7

True.

If there exists an x-intercept, the y-coordinate of that point must be zero. But, if y=0, $x^{2}+2=0\qquad/-2$ $x^{2}=-2$ which is not possible (a square of a real number can not be negative). There is no such x. So, there is no x-intercept.