Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.1 Rectangular Coordinates and Graphs - 2.1 Exercises: 7

Answer

True.

Work Step by Step

If there exists an x-intercept, the y-coordinate of that point must be zero. But, if y=0, $x^{2}+2=0\qquad/-2$ $x^{2}=-2$ which is not possible (a square of a real number can not be negative). There is no such x. So, there is no x-intercept.
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