Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.4 The Binomial Theorem - 11.4 Exercises - Page 1045: 39

Answer

$2401 p^4 - 2744 p^3 q + 1176 p^2 q^2 - 224 p q^3 + 16 q^4$

Work Step by Step

$(x+y)^n=\binom{n}{0}x^ny^0+\binom{n}{1}x^{n-1}y^1+...+\binom{n}{a}x^{n-a}y^a+..\binom{n}{n}x^{0}y^n$ Here: $n=4$, $x=7p$, $y=-2q$ $(7p-2q)^4=\binom{4}{0}(7p)^{6}(-2q)^0+\binom{4}{1}(7p)^{4-1}(-2q)^1+\binom{4}{2}(7p)^{4-2}(-2q)^2+\binom{4}{3}(7p)^{4-3}(-2q)^3+\binom{4}{4}(7p)^{4-4}(-2q)^4=$ $2401 p^4 - 2744 p^3 q + 1176 p^2 q^2 - 224 p q^3 + 16 q^4$
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