Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.4 The Binomial Theorem - 11.4 Exercises: 37

Answer

$p^4 + 8 p^3 q + 24 p^2 q^2 + 32 p q^3 + 16 q^4$

Work Step by Step

$(x+y)^n=\binom{n}{0}x^ny^0+\binom{n}{1}x^{n-1}y^1+...+\binom{n}{a}x^{n-a}y^a+..\binom{n}{n}x^{0}y^n$ Here: $n=4$, $x=p$, $y=2q$ $(p+2q)^4=\binom{4}{0}p^4(2q)^0+\binom{4}{1}p^{4-1}(2q)^1+\binom{4}{2}p^{4-2}(2q)^2+\binom{4}{3}p^{4-3}(2q)^3+\binom{4}{4}p^{4-4}(2q)^4=$ $p^4 + 8 p^3 q + 24 p^2 q^2 + 32 p q^3 + 16 q^4$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.