Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.4 The Binomial Theorem - 11.4 Exercises: 32

Answer

$m^4+4m^3n+6m^2n^2+4mn^3+n^4$

Work Step by Step

$(x+y)^n=\binom{n}{0}x^ny^0+\binom{n}{1}x^{n-1}y^1+...+\binom{n}{a}x^{n-a}y^a+..\binom{n}{n}x^{0}y^n$ Here: $n=4$, $(m+n)^4=\binom{4}{0}m^4n^0+\binom{4}{1}m^{4-1}n^1+\binom{4}{2}m^{4-2}n^2+\binom{4}{3}m^{4-3}n^3+\binom{4}{4}m^{4-4}n^4=$ $m^4+4m^3n+6m^2n^2+4mn^3+n^4$
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