Answer
$a_n=x+3n-3$
$x_8=x+21$
Work Step by Step
$a_1=x$
$a_2=x+3$
Then $d=a_2-a_1=(x+3)-x=3$.
$a_n=a_1+(n-1)d$
$a_n=x+(n-1)*3$
$\boxed{a_n=x+3n-3}$
$a_8=x+3*8-3$
$a_8=x+24-3$
$\boxed{x_8=x+21}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 11 - Further Topics in Algebra - 11.2 Arithmetic Sequences and Series - 11.2 Exercises - Page 1024: 29
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