Answer
$a_1=10+\sqrt{7}$
$a_2=10$
$a_3=10-\sqrt{7}$
$a_4=10-2\sqrt{7}$
$a_5=10-3\sqrt{7}$
Work Step by Step
$a_1=10+\sqrt{7}$
$a_2=10$
Determine the common difference $d$:
$d=a_2-a_1=10-(10+\sqrt{7})=-\sqrt{7}$
Then we have:
$a_3=a_2+d=10+(-\sqrt{7})=10-\sqrt{7}$
$a_4=a_3+d=10-\sqrt{7}+(-\sqrt{7})=10-2\sqrt{7}$
$a_5=a_4+d=10-2\sqrt{7}+(-\sqrt{7})=10-3\sqrt{7}$