Answer
$(-\infty,\frac{3}{5}]$
Work Step by Step
The denominator is always positive except at $x=\frac{25}{8}$, thus we need $5x-3\le0$ which gives $x\le\frac{3}{5}$ or $(-\infty,\frac{3}{5}]$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 1 - Equations and Inequalities - 1.7 Inequalities - 1.7 Exercises - Page 160: 76
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