Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.7 Inequalities - 1.7 Exercises - Page 160: 73

Answer

$[\frac{3}{2}, \infty)$

Work Step by Step

The denominator is always positive, thus we need $2x-3\ge0$ which gives $x\ge\frac{3}{2}$ or $[\frac{3}{2}, \infty)$
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