Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.7 Inequalities - 1.7 Exercises - Page 160: 74

Answer

$(-\infty, \frac{8}{9})$

Work Step by Step

The denominator is always positive, thus we need $9x-8\lt0$ which gives $x\lt\frac{8}{9}$ or $(-\infty, \frac{8}{9})$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.