Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.5 Applications and Modeling with Quadratic Equations - 1.5 Exercises - Page 132: 38

Answer

$11.6\ in$ and $23.2\ in$

Work Step by Step

Step1. Assume the shorter leg has a length of $x\ in$, the other leg would be $2x\ in$. Step2. Use Pythagorean Theorem, we have $x^2+(2x)^2=26^2$ or $5x^2=26^2$ Step3. Take the positive solution of the above, we have $x=\frac{26}{\sqrt 5}\approx11.6\ in$ Step4. Conclusion: one leg is $11.6\ in$, the other one is $23.2\ in$
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