Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set - Page 68: 23

Answer

$(3x+2)(x-1)$

Work Step by Step

$3x^{2}-x-2=$ two factors of $ac=-6$ whose sum is $b=-1$ are $-3$ and $+2 .$ Rewrite the middle term and factor in pairs. $3x^{2}-x-2=3x^{2}-3x+2x-2$ $=3x(x-1)+2(x-1)$ $=(3x+2)(x-1)$
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