Answer
$(2x-3)(3x-4)$
Work Step by Step
$6x^{2}-17x+12=$
two factors of $ac=+72$ whose sum is $b=-17$ are $-8$ and $-9.$
Rewrite the middle term and factor in pairs.
$6x^{2}-17x+12=6x^{2}-8x-9x+12$
$=2(3x-4)-3(3x-4)$
$=(2x-3)(3x-4)$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter P - Section P.5 - Factoring Polynomials - Exercise Set - Page 68: 28
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