Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set - Page 68: 24

Answer

$(2x-1)(x+3)$

Work Step by Step

$2x^{2}+5x-3=$ two factors of $ac=-6$ whose sum is $b=+5$ are $-1$ and $+6.$ Rewrite the middle term and factor in pairs. $2x^{2}+5x-3=2x^{2}+6x-x-3$ $=2x(x+3)-x+3)$ $=(2x-1)(x+3)$
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