Answer
$-2a$
Work Step by Step
RECALL:
(1) $\sin{(-t)} = -\sin{t}$
(2) $\cos{(-t)} = \cos{t}$
(3) $\tan{(-t)} = -\tan{t}$
Use the given and rule (1) above to obtain:
$=-\sin{t} -\sin{t}
\\=-a - a
\\=-2a$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 4 - Section 4.2 - Trigonometric Functions: The Unit Circle - Exercise Set - Page 548: 71
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