Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.2 - Trigonometric Functions: The Unit Circle - Exercise Set: 25

Answer

tan t = $\frac{8}{15}$ csc t = $\frac{17}{8}$ sec t =$\frac{17}{15}$ cot t = $\frac{15}{8}$

Work Step by Step

tan t is computed by $\frac{sin t}{cos t}$ tan t = $\frac{sin t}{cos t}$ =$\frac{\frac{8}{17}}{\frac{15}{17}}$ =$\frac{8}{15}$ csc t = $\frac{1}{sin t}$ = $\frac{1}{\frac{8}{17}}$ = $\frac{17}{8}$ sec t = $\frac{1}{cos t}$ = $\frac{1}{\frac{15}{17}}$ = $\frac{17}{15}$ cot t = $\frac{1}{tan t}$ = $\frac{1}{\frac{8}{15}}$ = $\frac{15}{8}$
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