Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.2 - Trigonometric Functions: The Unit Circle - Exercise Set - Page 548: 26

Answer

tan t = $\frac{3}{4}$ csc t = $\frac{5}{3}$ sec t = $\frac{5}{4}$ cot t = $\frac{4}{3}$

Work Step by Step

tan t is computed by $\frac{sin t}{cos t}$ tan t = $\frac{sin t}{cos t}$ =$\frac{\frac{3}{5}}{\frac{4}{5}}$ =$\frac{3}{4}$ csc t = $\frac{1}{sin t}$ = $\frac{1}{\frac{3}{5}}$ = $\frac{5}{3}$ sec t = $\frac{1}{cos t}$ = $\frac{1}{\frac{4}{5}}$ = $\frac{5}{4}$ cot t = $\frac{1}{tan t}$ = $\frac{1}{\frac{3}{4}}$ = $\frac{4}{3}$
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