## Precalculus (6th Edition) Blitzer

$x \approx 1.12$
Divide both sides of the equation by 4 to obtain $e^{7x}=\dfrac{10,273}{4}.$ The base in the exponential equation is $e$, so take the natural logarithm on both sides to obtain $\ln{e^{7x}}=\ln{\frac{10273}{4}}.$ Use the property $\ln{e^b}=b$ (where b=7x) on the left side to obtain $7x = \ln{\frac{10273}{4}}.$ Divide both sides by $7$ to obtain $x=\dfrac{\ln{\frac{10273}{4}}}{7}.$ Use a calculator and round-off the answer to two decimal places to obtain $x \approx 1.12.$