Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.4 - Exponential and Logarithmic Equations - Exercise Set - Page 488: 23

Answer

$x \approx 0.59$

Work Step by Step

The base in the exponential equation is 10, so take the common logarithm on both sides to obtain $\log{10^x} = \log{3.91}.$ Use the inverse property $\log{10^x} =x$ on the left side of the equation to obtain $x = \log{3.91}.$ Use a calculator and round-off the answer to two decimal places to obtain $x \approx 0.59.$
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