Answer
$\dfrac{1}{2}$
Work Step by Step
RECALL:
$\log_b{b^x} = x.$
Note that
$\sqrt{6}=6^{\frac{1}{2}}.$
Thus, the given expression can be written as
$\log_6{6^{\frac{1}{2}}}.$
Use the rule above to obtain
$\dfrac{1}{2}.$