Answer
$-3$
Work Step by Step
RECALL:
$\log_b{b^x} = x.$
Note that
$\dfrac{1}{8}=\dfrac{1}{2^3} = 2^{-3}.$
Thus, the given expression can be written as
$\log_2{2^{-3}}.$
Use the rule above t obtain
$-3.$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 3 - Section 3.2 - Exponential Functions - Exercise Set - Page 463: 27
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