Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.2 - Exponential Functions - Exercise Set: 16

Answer

$\log_{15}{x}=2$

Work Step by Step

RECALL: $b^y=x \longleftrightarrow \log_b{x} =y .$ Use the definition above to obtain $15^{2} = x \longrightarrow \log_{15}{x}=2.$ Thus, the equivalent logarithmic form of the given expression is $\log_{15}{x}=2.$
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