Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Test: 24

Answer

$-1\frac{2}{3}$

Work Step by Step

$-\frac{2}{7}\times(6-\frac{1}{6})$ $=-\frac{2}{7}\times(\frac{36}{6}-\frac{1}{6})$ $=-\frac{2}{7}\times\frac{35}{6}$ $=-(\frac{2}{7}\times\frac{35}{6})$ $=-(\frac{1}{1}\times\frac{5}{3})$ $=-\frac{5}{3}$ $=-1\frac{2}{3}$
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