Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Test - Page 325: 37

Answer

$\frac{13}{50}$

Work Step by Step

$\frac{1}{50}$ + $\frac{1}{5}$ + $\frac{1}{25}$ The LCD (least common denominator) is 50, so multiply $\frac{1}{5}$ by $\frac{10}{10}$ and $\frac{1}{25}$ by $\frac{2}{2}$ so their denominators equal 50. $\frac{1}{5}$ $\times$ $\frac{10}{10}$ = $\frac{10}{50}$ $\frac{1}{25}$ $\times$ $\frac{2}{2}$ = $\frac{2}{50}$ Now, add all three fractions together: $\frac{1}{50}$ + $\frac{10}{50}$ + $\frac{2}{50}$ = $\frac{13}{50}$
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