Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Test: 22

Answer

$21\frac{1}{3}$

Work Step by Step

$-\frac{16}{3}\div-\frac{3}{12}$ $=\frac{16}{3}\div\frac{1}{4}$ $=\frac{16}{3}\times\frac{4}{1}$ $=\frac{64}{3}$ $=21\frac{1}{3}$
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