Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Test: 16

Answer

$\frac{9a+4}{10}$

Work Step by Step

$\frac{9a}{10}+\frac{2}{5}$ $\longrightarrow$ convert to like fractions =$\frac{9a}{10}+\frac{2\times2}{5\times2}$ $\longrightarrow$ mutiply =$\frac{9a}{10}+\frac{4}{10}$ $\longrightarrow$ add numerators =$\frac{9a+4}{10}$
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