Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Test: 19

Answer

$\frac{3}{4}$

Work Step by Step

Find the least common denominator. $12=2\times2\times3$ $8=\underline2\times\underline2\times\underline2$ $24=2\times2\times2\times\underline3$ $LCD=2\times2\times2\times3=24$ $\frac{11}{12}-\frac{3}{8}+\frac{5}{24}$ $\longrightarrow$ convert to like fractions =$\frac{11\times2}{12\times2}-\frac{3\times3}{8\times3}+\frac{5}{24}$ $\longrightarrow$ simplify =$\frac{22}{24}-\frac{9}{24}+\frac{5}{24}$ $\longrightarrow$ subtract numerators =$\frac{22-9+5}{24}$ $\longrightarrow$ subtract =$\frac{18}{24}$ $\longrightarrow$ reduce =$\frac{18\div6}{24\div6}$ $\longrightarrow$divide =$\frac{3}{4}$
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