Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Test - Page 324: 14

Answer

$y^2$

Work Step by Step

$\frac{xy^3}{z}\times\frac{z}{xy}$ $\longrightarrow$ multiply numerators and denominators =$\frac{/\!\!x/\!\!yy^2/\!\!z}{/\!\!z/\!\!x/\!\!y}$ $\longrightarrow$ cancel common factors =$y^2$
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