Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Review: 38

Answer

$\frac{15}{4}=3\frac{3}{4}$

Work Step by Step

$\frac{21a}{4}\div\frac{7a}{5}=\frac{21a}{4}\times\frac{5}{7a} =\frac{3\times/\!\!7\times /\!\!a}{4}\times\frac{5}{/\!\!7\times /\!\!a} =\frac{3\times5}{4}=\frac{15}{4}=3\frac{3}{4}$
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