Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Review: 33

Answer

$\frac{9}{x^2}$

Work Step by Step

We can simplify by canceling out common factors of both fractions and then multiplying. Multiplying 2 negatives yields a positive product. $-\frac{24x}{5}\times-\frac{15}{8x^3}=-\frac{3\times/\!\!8\times /\!\!x}{/\!\!5}\times-\frac{3\times/\!\!5}{/\!\!8\times /\!\!x\times x^2}=\frac{3\times3}{x^2}=\frac{9}{x^2}$
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