Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Review - Page 319: 27

Answer

$\frac{2}{3}$

Work Step by Step

$\frac{part}{whole}=\frac{8}{12}=\frac{8\div4}{12\div4}=\frac{2}{3}$
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