Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 10 - Section 10.2 - Integrated Review - Operations on Polynomials: 30

Answer

$125x^{22}b^{28}$

Work Step by Step

$(5x^{4}y^{6})^{3}(x^{2}y^{2})^{5}$ $=(5^{3})[(x^{4})^3][(y^{6})^3][(x^{2})^5)][(y^{2})^{5}]$ $=(5\times5\times5)(x^{4\times3})(x^{2\times5})(y^{6\times3})(y^{2\times5})$ $=(25\times5)(x^{12})(x^{10})(y^{18})(y^{10})$ $=125(x^{12+10})(y^{18+10})$ $=125x^{22}b^{28}$
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