Answer
$128y^{6}z^{7}$
Work Step by Step
$(8y^{3}z)^{2}(2z^{5})$
$=(8^{2})[(y^{3})^2](z^{2})(2z^{5})$
$=(8\times8)(y^{3\times2})(2z^{2+5})$
$=(64)(y^{6})(2z^{7})$
$=128y^{6}z^{7}$
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