Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 10 - Section 10.2 - Integrated Review - Operations on Polynomials: 28

Answer

$128y^{6}z^{7}$

Work Step by Step

$(8y^{3}z)^{2}(2z^{5})$ $=(8^{2})[(y^{3})^2](z^{2})(2z^{5})$ $=(8\times8)(y^{3\times2})(2z^{2+5})$ $=(64)(y^{6})(2z^{7})$ $=128y^{6}z^{7}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.