Answer
$32y^{5}$
Work Step by Step
$(2y)^{5}$
$=2^{5}y^{5}$
$=(2\times2\times2\times2\times2)y^{5}$
$=(4\times2\times2\times2)y^{5}$
$=(8\times2\times2)y^{5}$
$=(16\times2)y^{5}$
$=32y^{5}$
Prealgebra (7th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321955048
ISBN 13:
978-0-32195-504-3
Chapter 10 - Section 10.2 - Integrated Review - Operations on Polynomials - Page 712: 22
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