Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.7 Events Involving And; Conditional Probability - Exercise Set 11.7 - Page 746: 5

Answer

$\frac{1}{4}$

Work Step by Step

If A and B are independent events, then P(A and B) = P(A)*P(B). (A+B): a color other than red each time A: green or yellow B: green or yellow P(A) = $\frac{3}{6}$ P(B) = $\frac{3}{6}$ Both events A and B are independent: P(A and B) = $\frac{3}{6}$ .$\frac{3}{6}$ = $\frac{1}{4}$
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