Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.7 Events Involving And; Conditional Probability - Exercise Set 11.7 - Page 746: 13

Answer

$\frac{1}{3}$

Work Step by Step

If A and B are independent events, then P(E) = P(A)*P(B). A: {2,4,6} first time P(A) = $\frac{3}{6}$ B: A number greater than 2 the second role. P(B) = $\frac{4}{6}$ Both events A and B are independent, so P(E) = $\frac{3}{6}$ .$\frac{4}{6}$ = $\frac{1}{3}$
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