Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.7 Events Involving And; Conditional Probability - Exercise Set 11.7 - Page 746: 17

Answer

$\frac{1}{169}$

Work Step by Step

If A and B are independent events, then P(E) = P(A)*P(B) You draw a card from a standard deck of playing cards. Then, after the card that you drew is replaced, you draw another card. Find the probability of some event, E, happening. Let A be the first event, B be the second event, and so on. E: a king each time A: {4} a king B: {4} a king P(A) = $\frac{4}{52}$ P(B) = $\frac{4}{52}$ Both events A and B are independent: P(E) = $\frac{4}{52}$ .$\frac{4}{52}$ = $\frac{1}{169}$
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