## Basic College Mathematics (9th Edition)

Area of the Triangle = $A$ = 139.15 cm$^{2}$ Perimeter of the Triangle = $P$ = 58.9 cm
Area of a Triangle: $A$ = $\frac{1}{2}$$b$$h$ Therefore: $A$ =$\frac{1}{2}$(25.3 cm)(11 cm) $A$ = 139.15 cm$^{2}$ Perimeter of a Triangle: $P$ = $a$ + $b$ + $c$ Therefore: $P$ = 25.3 cm + 18 cm + 15.6 cm $P$ = 58.9 cm