Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 8 - Geometry - 8.5 Triangles - 8.5 Exercises: 5

Answer

Area of the Triangle = $A$ = 139.15 cm$^{2}$ Perimeter of the Triangle = $P$ = 58.9 cm

Work Step by Step

Area of a Triangle: $A$ = $\frac{1}{2}$$b$$h$ Therefore: $A$ =$\frac{1}{2}$(25.3 cm)(11 cm) $A$ = 139.15 cm$^{2}$ Perimeter of a Triangle: $P$ = $a$ + $b$ + $c$ Therefore: $P$ = 25.3 cm + 18 cm + 15.6 cm $P$ = 58.9 cm
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